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Carbon disulfide burns with oxygen to form carbon dioxide and sulfur dioxide in the following manner:


CS2 + 3 O2 CO2 + 2 SO2


What is the volume of sulfur dioxide (SO2 gas) formed when 2.00 moles of carbon disulfide (CS2) are burned? The reaction is taking place at STP.


5.6 liters

22.4 liters

89.6 liters

44.8 liters

Verified Answer :

taskmasters

The balanced chemical reaction is written as:

CS2 + 3 O2 CO2 + 2 SO2

We are given the amount of carbon disulfide to be used for the reaction. We use this amount as the starting point for the calculations.

2.0 mol CS2 ( 2 mol SO2 / 1 mol CS2 ) ( 22.4 L / 1 mol ) = 89.6 L

Therefore, the correct answer is the third option.

Dejanras

Answer is: 89.6 liters.

Balanced chemical reaction:

CS₂ + 3O₂ → CO₂ + 2SO₂.

n(CS₂) = 2.00 mol; amount of carbon disulfide.

From balanced chemical reaction: n(CS₂) : n(SO₂) = 1 : 2.

n(SO₂) = 2 · 2 mol.

n(SO₂) = 4.00 mol; amount of sulfur dioxide.

V(SO₂) = n(SO₂) · Vm.

V(SO₂) = 4 mol · 22.4 L/mol.

V(SO₂) = 89.6 L; volume of sulfur dioxide.

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