Answer:
0.0180 is the volume of the water in liters would the bar displace.
Explanation:
The length metal bar = l = 3.0 cm
The width metal bar = w =3.0 cm
The height metal bar = h = 2.0 cm
Volume of the cuboid = \(l\times w\times h\)
Volume of the metal bar = V
\(V=l\times w\times h=3.0 cm\times 3.0 cm\times 2.0 cm=18.0 cm^3\)
\(1 cm^3= 1 mL\)
\(18.0 cm^3=18.0 mL\)
1 mL = 0.001 L
\(18.0 mL= 18.0 \times 0.001 L=0.0180 L\)
0.0180 is the volume of the water in liters would the bar displace.
