for the function f(x) = –(x 1)2 4, identify the vertex, domain, and range. the vertex is (–1, 4), the domain is all real numbers, and the range is y ≥ 4. the vertex is (–1, 4), the domain is all real numbers, and the range is y ≤ 4. the vertex is (1, 4), the domain is all real numbers, and the range is y ≥ 4. the vertex is (1, 4), the domain is all real numbers, and the range is y ≤ 4.
f(x) = -(x + 1)^2 + 4
Vertex = (-1, 4)
Domain is all real numbers.
Range is f(x) <= 4
Answer:
The correct option is 2.
Step-by-step explanation:
The given function is
\(f(x)=-(x+1)^2+4\) ..... (1)
The standard form of a parabola is
\(y=a(x-h)^2+k\) .....(2)
Where, (h,k) is the vertex and a is stretch factor.
On comparing (1) and (2), we get
\(h=-1\)
\(k=4\)
\(a=-1\)
The vertex of the parabola is (-1,4). Since a=-1<0, therefore it is a downward parabola. Domain of an downward parabola is all real numbers.
The vertex of a downward parabola is the point of maxima. So the range of the function can not be more that 4.
Therefore the domain is all real numbers, and the range is y ≤ 4. Option 2 is correct.