if p(x) = x2 – 1 and q(x)=5(x-1), which expression is equivalent to (p – q)(x)? a: 5(x – 1) – x2 – 1 b: (5x – 1) – (x2 – 1) c: (x2 – 1) – 5(x – 1) d: (x2 – 1) – 5x – 1
p(x) = x^2 - 1
q(x) = 5(x - 1)
(p - q)(x) = (x^2 - 1) - 5(x - 1)
Answer:
Option c is true.
( \((p-q)(x)=(x^2-1)-5(x-1)\) ) .
Step-by-step explanation:
We are given:
\(p(x) = x^2-1\) and \(q(x)=5(x-1)\).
Now we are asked to find the expression of:
\((p-q)(x)\)
We know that the expression (p-q)(x) could also be written as:
\((p-q)(x)=p(x)-q(x)\)
Hence, \((p-q)(x)=(x^2-1)-(5(x-1))\\\\(p-q)(x)=(x^2-1)-5(x-1)\)
Hence option c is true i.e. the expression is:
\((p-q)(x)=(x^2-1)-5(x-1)\)