if f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)? a: 6 – 3 – (4 3)2 b: 6 – 3 – (4 – 32) c: 6(3) – 4 32 d:6(3) – 4 – 32
f(x) = 4 - x^2
g(x) = 6x
(g - f)(x) = 6x - (4 - x^2)
(g - f)(3) = 6(3) - (4 - 3^2) = 6(3) - 4 + 3^2
Answer:
Option c is correct
\(6(3) - 4 +3^2\)
Step-by-step explanation:
Given the functions:
\(f(x) = 4-x^2\)
\(g(x) = 6x\)
We have to find \((g-f)(3)\).
\((g-f)(3) = g(3) -f(3)\)
Substitute x = 3 in the given functions we have;
\(f(3) = 4 -3^2\)
\(g(3) = 6(3)\)
Substitute these we have;
\((g-f)(3) = 6(3) - (4 -3^2)\)
⇒\((g-f)(3) = 6(3) - 4 +3^2\)
Therefore, the value of \((g-f)(3)\) is, \(6(3) - 4 +3^2\)