Answered

Math Questions!



07.02 LC)


Alicia rolls two fair number cubes numbered from 1 to 6. She first defines the sample space, as shown below:


(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)


Based on the sample space, what is the probability of getting a total of 7?


4 over 36


5 over 36


6 over 36


8 over 36






(07.01 MC)


The number of chips of different colors in Gail's bag is shown below:

•3 blue chips

•4 pink chips

•8 white chips


Gail takes out a chip from the bag randomly without looking. She replaces the chip and then takes out another chip from the bag. What is the probability that Gail takes out a white chip in both draws?


8 over 15 multiplied by 7 over 14 is equal to 56 over 210


8 over 15 plus 7 over 14 is equal to 217 over 210


8 over 15 plus 8 over 15 is equal to 16 over 15


8 over 15 multiplied by 8 over 15 is equal to 64 over 225






Sue used a probability simulator to roll a 6-sided number cube and flip a coin 100 times. The results are shown in the tables below:




Number on cube vs Number of times rolled


1 18

2 25

3 12

4 32

5 3

6 10



Heads = 56


Tails = 44





Using Sue's simulation, what is the probability of rolling a 2 on the number cube and the coin landing heads up?


81 over 100


56 over 100


1400 over 10000


1100 over 10000

Verified Answer :

dalendrk

\(Q1.\\\Omega=\{(x;\ y)|\ x,\ y\in\{1;\ 2;\ 3;\ 4;\ 5;\ ;6\}\}\\\\\overline{\overline{\Omega}}=6\cdot6=36\\\\A=\{(1;\ 6);\ (2;\ 5);\ (3;\ 4);\ (4;\ 3);\ (5;\ 2);\ (6;\ 1)\}\\\\\overline{\overline{A}}=6\\\\P(A)=\dfrac{\overline{\overline{A}}}{\overline{\overline{\Omega}}}\Rightarrow P(A)=\dfrac{6}{36}\leftarrow Answer\)


\(Q2.\\3+4+8=15-number\ of\ all\ chips\\\\8\ white\ chips\\\\P(B)=\dfrac{8}{15}\cdot\dfrac{8}{15}=\dfrac{64}{225}\leftarrow Answer\)


\(Q3.\\25-number\ of\ 2\\56-number\ of\ heat\\100-number\ of\ all\\\\\dfrac{25}{100}\cdot\dfrac{56}{100}=\dfrac{1400}{10000}\leftarrow Answer\)

\(Question \ 1)\) 

\(Two \ numbers \ written \ in \ a \ certain \ order \ are \ known \ as\)
\(ordered \ pairs.\) 

\(Ordered \ pair \ that \ add \ up \ to \ 7 \ (6,1) (5,2) (4,3) (3,4) (2,5) (1,6)\)

\(P(A)= \dfrac{6}{36}\) 

\(Question \ 2)\) \(3+4+8=15 \ Total \ number \ of \ chips\)

\(Where \ 8 \ represents \ = white\) 

\(P(B)= \dfrac{8}{15}* \dfrac{8}{15} = \dfrac{64}{225} = Solution\) 

\(Question \ 3)\)

\(Convert \ to \ fraction \ and \ muliply\)

\(The \ numerator \ in \ a \ fraction \ represents \ the \ number \ of \ pieces \\) 
\(selected.\)\(If \ the umerator \ is \ larger \ than \ the \ denominator, the \ number \ is \ larger \\)\(than \ one.\)

\(The \ denominator \ in \ a \ fraction \ represents \ the \ total \ number \\)
\(of \ equal \ size \ pieces \ that \ make \ up \ a \ whole.\)

\(\dfrac{25}{100} * \dfrac{56}{100}= \dfrac{1400}{10000}\)

Related Questions