To create an entry code, you must first choose 3 letters and then, 6 single-digit numbers. How many different entry codes can you create?
Answer:
17576000000
Step-by-step explanation:
26 x 26 x 10 x 10 x 10 x 10 x 10 x 10
Using the Fundamental Counting Theorem, it is found that you can create 17,576,000,000 different entry codes.
It is a theorem that states that if there are n things, each with \(n_1, n_2, \cdots, n_n\) ways to be done, each thing independent of the other, the number of ways they can be done is:
\(N = n_1 \times n_2 \times \cdots \times n_n\)
In this problem, for each letter there are 26 possible outcomes and for each digit there are 10 possible outcoms, hence:
\(N = 26^3 \times 10^6 = 17,576,000,000\)
More can be learned about the Fundamental Counting Theorem at https://brainly.com/question/24314866
#SPJ2