Verified Answer :
Answer : The number of moles of \(Ba(OH)_2\) required are, 0.2125 moles.
Explanation : Given,
Moles of \(HC_2H_3O_2\) = 0.425 mole
The balanced chemical reaction will be:
\(Ba(OH)_2+2HC_2H_3O_2\rightarrow Ba(C_2H_3O_2)_2+2H_2O\)
From the balanced chemical reaction we conclude that,
As, 2 moles of \(HC_2H_3O_2\) completely neutralize by 1 mole of \(Ba(OH)_2\)
So, 0.425 moles of \(HC_2H_3O_2\) completely neutralize by \(\frac{0.425}{2}=0.2125\) mole of \(Ba(OH)_2\)
Therefore, the number of moles of \(Ba(OH)_2\) required are, 0.2125 moles.
The number of moles of Ba(OH)₂ that are required to completely neutralize the 0.425 mole of HC₂H₃O₂ is 0.2125 mole
From the question,
We are to determine the number of moles of Ba(OH)₂ that are required to completely neutralize 0.425 mole of HC₂H₃O₂
First, we will write a balanced chemical equation for the reaction,
The balanced chemical equation for the reaction is
Ba(OH)₂ + 2HC₂H₃O₂ → Ba(C₂H₃O₂)₂ + 2H₂O
This means 1 mole of Ba(OH)₂ is required to completely neutralize 2 moles of HC₂H₃O₂
Now,
Let number of moles of Ba(OH)₂ that would neutralize the HC₂H₃O₂ be x
From the given information
Number of moles of HC₂H₃O₂ = 0.425 mole
Since
1 mole of Ba(OH)₂ is required to completely neutralize 2 moles of HC₂H₃O₂
Then,
x mole of Ba(OH)₂ would be required to completely neutralize 0.425 mole of HC₂H₃O₂
x = \(\frac{0.425 \times 1 }{2}\)
x = 0.2125
Hence, the number of moles of Ba(OH)₂ that are required to completely neutralize the 0.425 mole of HC₂H₃O₂ is 0.2125 mole
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