Answer:
The sum is \(6a^2-2ab+2b+9\)
Step-by-step explanation:
Given two expression
\((2a^2 + ab + 2b)\) and \((4a^2 − 3ab + 9)\)
We have to find the sum of above two expression.
\((2a^2 + ab + 2b)+(4a^2 - 3ab + 9)\)
Combining like terms we get
\((2a^2+4a^2)+(ab-3ab)+2b+9\)
= \(6a^2-2ab+2b+9\)
The sum is \(6a^2-2ab+2b+9\)
