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Algebra 2 Help!


What are the sine, cosine, and tangent of 5pi/3 radians?


sin Θ = -sqrt 3/2; cos Θ = 1/2; tan Θ = -sqrt 3


sin Θ = sqrt 3/2; cos Θ = -1/2; tan Θ = sqrt 3


sin Θ = sqrt 3/2; cos Θ = 1/2; tan Θ = sqrt 3


sin Θ = -sqrt 3/2; cos Θ = -1/2; tan Θ = -sqrt 3

Verified Answer :

meerkat18

Base on the question that ask to calculate the sine, cosine, and tangent of 5pi/3 radians and base on my further calculation, I would say that the answer would be sin Θ = -sqrt 3/2; cos Θ = -1/2; tan Θ = -sqrt 3. I hope you are satisfied with my answer and feel free to ask for more if you have question and further clarification 

calculista

Answer:

\(sin(\frac{5\pi }{3})=-\frac{\sqrt{3}}{2}\) ; \(cos(\frac{5\pi }{3})=\frac{1}{2}\) ; \(tan(\frac{5\pi }{3})=-\sqrt{3}\)

Step-by-step explanation:

we know that

\(\pi \ radians=180\ degrees\)

so

\(\frac{5\pi }{3}\ radians=300\ degrees\)

The angle belong to the IV quadrant

therefore

The sine is negative

The cosine is positive

The tangent is negative

\(360\°-300\°=60\°\)

so

\(sin(\frac{5\pi }{3})=-sin(60\°)=-\frac{\sqrt{3}}{2}\)

\(cos(\frac{5\pi }{3})=cos(60\°)=\frac{1}{2}\)

\(tan(\frac{5\pi }{3})=-tan(60\°)=-\sqrt{3}\)

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