anasngreemichel
Answered

Hi, I have a lab question and I'm kind of confused on how to approach it.


Evaluation of molar enthalpy of dissociation of formic acid, deltaHdiss.


Given:

H1 = -58010 J/mol; H2 = -59758.4J/mol


They tell use to use Hess's Law to determine the enthalpy of dissociation


Thanks!

Verified Answer :

meerkat18

Hess' Law uses manipulation of the equations used to form the correct equation in total.
 
 1. H3O+ + OH- > 2H2O                             H1= -58010 J/mol

 2. HCOOH + OH- > H2O + HCOO-          H2 = -59758 J/mol

 
2. HCOOH + OH- > H2O + HCOO-           H2 = -59758 J/mol

1. [x-1] = 2H2O > OH + H3O                       H1 = 580101 J/mol

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HCOOH + H2O > H3O + HCOO                     H= -1748 J/mol

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