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A spherical water tank has a diameter of 42 feet. How much water can the tank hold when full?

A10,561π cubic feet

B12,348π cubic feet

C15,934π cubic feet

D21,568π cubic feet

Verified Answer :

SyntaxError

We know that the radius is 21 by dividing the diameter by half

volume of a sphere is v = \(\frac{4}{3} \pi r^3\)

\(v= \frac{4}{3} \pi 21^3=12,348[tex] \pi\) [/tex]

Answer is B

Hagrid

This problem asked us to compute for the volume of the tank. The shape of the tank is a sphere. Hence the volume of the sphere is (4/3) of pi times the cube of the radius. Radius is twice the diameter. Since the diameter is 42 feet the radius is 21 feet. Given this we can already find the volume. The volume is 
V = (4/3)pi(r^3)
= pi(4/3)(21^3)
= pi(4/3)(9216)
= pi(12348)
= 12,348pi ft.^3

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