Verified Answer :

well , we now the password would be :

3 _ _ _ 

and if there is no 0 and 9, the combination must be between 1 to 8

So the possibility of password would be :

8 x 8 x 8 = 512 possibilities

The answer is option B.

Hope this helps

MrRoyal

If digits can be repeated, the number of possible passwords are 512

How to determine the number of passwords?

The given parameters are:

Usable digits = 8 i.e. no 0 and 9

First digit = 3

Length = 4

The above parameters mean that:

  • The first digit can only be 1 digit
  • The other digits can be any of the 8 digits

So, the number of passwords is:

Combination = 1 8 8 * 8

Evaluate

Combination = 512

Hence, if digits can be repeated, the number of possible passwords are 512

Read more about combination at:

https://brainly.com/question/11732255

#SPJ5

Related Questions