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If 33.7 grams of LiOH dissolve in enough water to make a 231-gram solution, what is the concentration in percent by mass? A) 8.73% LiOH. B) 14.6% LiOH.. . C) 6.85% LiOH. D) 12.7% LiOH

Verified Answer :

Willchemistry

w/w% = solute / mass of solution

w/w% = 33.7 / 231

w/w% = 0.146

= 0.146 x 100 => 14.6%

Answer B

hope this helps!

Answer: The correct answer is option B.

Explanation:

The concentration in percent by mass is defined as the mass of solute present in given amount of solution.

\(\%\text{ mass}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100\)

We are given:

Mass of solute = 33.7 grams

Mass of solution = 231 grams

Putting values in above equation, we get:

\(\%\text{ mass of LiOH}=\frac{33.7}{231}\times 100=14.58\%\approx 14.6\%\)

Hence, the correct answer is option B.

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