If f(x) =tan(2x) then f'(pi/6)?
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f ( x ) = tan ( 2 x );f ( x ) = (1 / cos² x )· ( 2 x ) = 2 / cos² xf` ( π/6 ) = 2 / cos² (π/6) = 2 / (√3/2)² = 2 : 3/4 = 8/3
( x ) = (1 / cos² x )· ( 2 x )
