A 68 g bar of gold is cut into 3 equal pieces. How does the density of each piece compare to the density of the original gold bar?
Answer:
The density would be same.
Step-by-step explanation:
\(\because \text{Density}=\frac{\text{Mass}}{\text{Volume}}\)
Here, the mass of the original box = 68 g,
Suppose V be the volume of the original box,
Then, the density of the original box = \(\frac{68}{V}\)
After cutting this box into 3 equal pieces,
Mass of each piece = \(\frac{68}{3}\)
While, the volume of each piece = \(\frac{V}{3}\)
So, the density of each piece = \(\frac{68/3}{V/3}\) = \(\frac{68}{V}\)
Hence, the density would be same.