Probablility that that first marble is red:
\(P_{red} = \frac{red}{total}\)
\(P_{red} = \frac{5}{5+3}\)
Probability that the second marble is green:
\(P_{green} = \frac{green}{total(new)}\)
\(P_{green}= \frac{3}{4+3}\) (because 1 red is now gone)
\(P_{total}=P_{red} \times P_{green}\)
\(P_{total}= \frac{6}{8} \times \frac{3}{7} = \frac{18}{56} = \frac{9}{28} \approx 32.1\%\)
