2H₂ ₍g₎ + O₂ ₍g₎ --------> 2H₂O ₍l₎
If mass of water = 447 g
And mol = \(\frac{MASS}{MOLAR MASS}\)
then mol of H₂O = \(\frac{447 g}{((16)+(1 * 2) g / mol}\)
= 24.83 mol
Mole ratio of H₂O : O₂ ≡ 2 : 1
Since mole of H₂O = 24.83 mol
then mole of O₂ = 24.83 mol ÷ 2
= 12.42 mol
Thus Mass of O₂ = 12.42 mol (16 2) g / mol
= 397.28 g
