Answer:
The surface area is \(380\ in^{2}\)
Step-by-step explanation:
we know that
The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces
so
\(SA=b^{2}+4[\frac{1}{2}(b)(l)]\)
where
\(b=10\ in\)
\(l=14\ in\) -----> the slant height
substitute the values
\(SA=10^{2}+4[\frac{1}{2}(10)(14)]\)
\(SA=380\ in^{2}\)
