Xavier is roller skating at 14 km/h and tosses a set of keys on the ground at 8 km/h. The speed of the keys relative to the ground is km/h.
The speed of the keys with respect to the ground is given by:
\(V_{k-g} = V_{k-s} + V_{s-g}\)
Where,
Vk-s: Speed of the keys with respect to the skater
Vs-g: Speed of the skater compared to the ground
Substituting values in the equation we have:
\(V_{k-g} = 8 + 14
\)
\(V_{k-g} = 22 \frac{Km}{h}
\)
Answer:
The speed of the keys relative to the ground is 22 km / h.
The speed of the keys relative to the ground is determined as 22 km/h.
The speed of the key relative to the ground is calculated as follows;
Vk/g = Va + Vb
where;
Vk/g = 14 km/h + 8 km/h
Vk/g = 22 km/h
Thus, the speed of the keys relative to the ground is determined as 22 km/h.
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