Answer:
Option C is correct
\(x^2+3x-28\)
Step-by-step explanation:
Given the function:
\(f(x) = x+7\) and \(g(x) = x-4\)
we have to find the \(f(x) \cdot g(x)\)
\(f(x) \cdot g(x)\)
⇒\((x+7) \cdot (x+4)\)
Distribute the first term of the first expression to the second expression and second term of the first expression to the second expression.
⇒\(x(x-4)+7(x-4)\)
Using distributive property: \(a\cdot(b+c) = a\cdot b+ a\cdot c\)
\(x^2-4x+7x-28\)
Combine like terms;
\(x^2+3x-28\)
Therefore, \(f(x) \cdot g(x)\) we get, \(x^2+3x-28\)
