Verified Answer :

caylus

Hello,

\(x^2+3x+3=0\\ \Delta=9-4*3=-3\\ x= \dfrac{-3-i*\sqrt{3}}{2} \ or\ x= \dfrac{-3+i*\sqrt{3}}{2} \\\)

\(x^2 + 3x + 3 = 0\) 

\(Apply \ the \ Quadratic \ Formula\) 

\(Given \ the \ general \ form \ ax^2+bx+c=0\)\(there \ exists \ two \ solutions \ where: a=1, b=3 \ and \ c=3\) 

\(x= \dfrac{-3+ \sqrt{3i}}{2}, \dfrac{-3- \sqrt{3i} }{2}\) 


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