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The chemical reaction of the reactants, NaCH3COO and HCl, is written as follows:

NaCh3COO + HCl = NaCl + CH3COOH

To balance it, the number of atoms of an element in one side should be equal to the other side. By looking at the reaction, I believe it is already balanced. They have 1 is to 1 ratios.

Answer:

\(CH_3COONa~+~HCl~->~CH_3COOH~+~NaCl\)

Explanation:

This is an acid-base reaction in which the HCl is the acid and the \(CH_3COONa\) is the base.

In the balanced reaction, we will have a double replacement reaction. In which the cation of  \(CH_3COONa\) (in this case \(Na^+\)) will be exchanged by the hydronium ion \(H^+\) from the \(HCl\). Similarly the anion of \(HCl\) (\(Cl^-\) ) would bond with the cation \(Na^+\) to form \(NaCl\).

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