Answer:
\(\sqrt{2} (3\sqrt{2} +\sqrt{14})=6+2\sqrt{7}\)
Step-by-step explanation:
Given : \(\sqrt{2} (3\sqrt{2} +\sqrt{14})\)
Solution:
\(\sqrt{2} (3\sqrt{2} +\sqrt{14})\)
\(3*2+\sqrt{28})\)
\(6+2\sqrt{7}\)
Thus , \(\sqrt{2} (3\sqrt{2} +\sqrt{14})=6+2\sqrt{7}\)
Thus the solution is irrational since square root 7 does not have a perfect square and equal to 6+2square root of 14
