Answer:
\(\text{Perimeter of counter-top}=112\text{ inches}\)
\(\text{Area of counter-top}=784\text{ inches}^2\)
Step-by-step explanation:
We have been given that a square counter-top has a side length of 28 inches. We are asked to find the perimeter and area of the counter-top.
We know that perimeter of a square is 4 times its side length.
\(\text{Perimeter of counter-top}=4\times 28\text{ inches}\)
\(\text{Perimeter of counter-top}=112\text{ inches}\)
Therefore, the perimeter of the counter-top is 112 inches.
We know that area of square is square of side length of square.
\(\text{Area of counter-top}=(28\text{ inches})^2\)
\(\text{Area of counter-top}=784\text{ inches}^2\)
Therefore, the area of the counter-top is 784 square inches.
