Answer:
6.19 L
Step-by-step explanation:
We are given that
Number of moles of argon gas=0.8 moles
Pressure =P=5.3 atm
Temperature =T=227 degree Celsius=\(227+273=500k\)
We have to find the volume of the container needed to store the argon gas.
We know that
\(PV=nRT\)
Where R=0.082051 L atm/ mol k
Substitute the values in the given formula
\(5.3\times V=0.8\times 500\times 0.82051\)
\(V=\frac{0.8\times 0.082051\times 500}{5.3}=6.19 L\)
Hence, the volume of container needed to store the gas=6.19 L
