If a plant manufacturing carpet backing has a cylindrical tank that is 3 meters high and is 6 meters in diameter. What is the volume of the tank? Assume that 3.14 is the value for pi.
h = 3 m, d = 6 m , so: r = 3 m;
The volume of the tank is:
V = r² π h = 3² · 3.14 · 3 = 9 · 3.14 · 3 = 27 · 3.14 = 84.78 m³
Answer:
The volume of the tank is \(84.78\ m^{3}\)
Step-by-step explanation:
we know that
The volume of a cylinder is equal to
\(V=\pi r^{2}h\)
In this problem we have
\(r=6/2=3\ m\) -----> the radius is half the diameter
\(h=3\ m\)
substitute
\(V=(3.14)(3^{2})(3)=84.78\ m^{3}\)