Verified Answer :

musicotic

\(x^6=x^9\implies x^9-x^6=0\implies x^6(x^3-1)=0\implies x=0, x^3=1\). The values of \(x\) that satisfy \(x^3=1\) are \(x=1, x=\frac{-1+i\sqrt{3}}{2}, x=\frac{-1-i\sqrt{3}}{2}\)

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