Answer:
3 package of cups and 4 packages of napkins
Step-by-step explanation:
Given: sixty people are invited to a party.There are 24 cups in a package and 18 napkins in a package.
To Find: least number of packages of cups and napkins that can be bought if each party guest gets one cup and one napkin.
Solution:
Number of cups in a package = \(24\)
Number of napkins in a package = \(18\)
let total number of package of cups be = \(\text{x}\)
equation of total cups bought = \(24\times\text{x}\)
let total number of package of napkins be = \(\text{y}\)
equation of total napkins bought = \(18\times\text{y}\)
Total people invited to the party = \(60\)
as party guest gets one cup and one napkin
total cups required = \(60\)
total package of cups bought
\(24\times\text{x}\)≥ \(60\)
\(\text{x}\)≥\(\frac{60}{24}\)
\(\text{x}\)≥\(2.5\)
number of package should be an integer therefore \(\text{x}=3\)
total napkins required = \(60\)
\(18\times\text{y}\)≥ \(60\)
\(\text{y}\)≥\(\frac{10}{3}\)
as number of package are integer y must be 4
Least number of packages of cups bought are 3 and napkins is 4
