Answer:
\(\frac{1}{10}\text{ times}\)
Step-by-step explanation:
Given,
The numbers are,
4,385, 3,899
∵ 4385 = 4000 + 300 + 80 + 5
And, 3899 = 3000 + 800 + 90 + 9
So, the value of 3 in 4385 = 300
The value of 3 in 3899 = 3000
\(\because \frac{\text{The value of 3 in 4385}}{\text{The value of 3 in 3899}}=\frac{300}{3000}\)
\(=\frac{1}{10}\)
Hence, the value of 3 in 4,385 is \(\frac{1}{10}\) times greater than the value of the 3 in 3,899.