a quarterback throws a football at 40.0 km/hr to a receiver 50.0 yd away. how much time does it take the ball to reach the receiver?
t=d/s
40km/h x 1093.61yd/1km x 1h/60min x 1min/60s
40 x 1093.61 = 43744.4yd
60 x 60 = 3600sec
43744.4/3600= 12.15
distance/speed=time : 50yd/12.15yd/sec = 4.11sec
answer: 4.11sec
Explanation:
Given that,
The speed of a football, v = 40 km/h
The distance between a quarterback and a receiver is, d = 50 yards
To find,
The time taken by the ball to reach the receiver.
Solution,
First km/h is converted to m/s.
\(40\ km/h=\dfrac{40\times 1000}{3600}\\\\=11.11\ m/s\)
Also, \(1\ yd=0.9144\ m\\\\50\ yd=45.72\ m\)
Let t is the time taken by the ball to reach the receiver. We know that,
\(\text{Speed}=\dfrac{\text{distance}}{\text{time}}\)
So,
\(t=\dfrac{d}{v}\)
Put all the values,
\(t=\dfrac{45.72}{11.11}\\\\t=4.115\ s\)
or
\(t=4.12\ s\)
Answer:
The time taken by the ball to reach the receiver is \(4.12\ s\).
Reference,
https://brainly.com/question/10812167