A spherical ball of lead has a diameter of 2.5 cm . What is the mass of the sphere if lead has a density of 11.34 g/cm3? (The volume of a sphere is (43)πr3 where r is the radius.)
mass = volume x density
volume = πr²
since Diameter = 2.5 cm
then radius = 1.25cm
∴ volume = π x (1.25cm)³
≈ 6.1359 cm³
Thus mass = 6.1359 cm³ x 11.34 g / cm³
= 69.58 g
Answer : The mass of sphere is 92.727 grams.
Explanation :
To calculate the volume of sphere, we use the formula:
\(V=\frac{4}{3}\pi r^3\) .....(1)
where,
r = radius of sphere
Given :
Diameter of sphere = 2.5 cm
Radius of sphere = \(\frac{Diameter}{2}=\frac{2.5cm}{2}=1.25cm\)
Now put all the given values in the above formula (1), we get:
\(V=\frac{4}{3}\times 3.14\times (1.25cm)^3\)
\(V=8.177cm^3\)
To calculate mass of a substance, we use the equation:
\(Density=\frac{Mass}{Volume}\) .....(2)
Putting values in above equation (2), we get:
\(11.34g/cm^3=\frac{Mass}{8.177cm^3}\)
\(Mass=92.727g\)
Hence, the mass of sphere is 92.727 grams.