Answer:
No, order in which we subtract the x coordinates and y coordinates does nor matter
Step-by-step explanation:
Let the two points be \(\left ( x_1,y_1 \right )\,\,,\,\,\left ( x_2,y_2 \right )\)
By distance formula: distance between points \(\left ( x_1,y_1 \right )\,\,,\,\,\left ( x_2,y_2 \right )\) is equal to \(\sqrt{\left ( x_2-x_1 \right )^2+\left ( y_2-y_1 \right )^2}\)
We know that \(\left ( x_2-x_1 \right )^2=\left ( x_1-x_2 \right )^2\) and \(\left ( y_2-y_1 \right )^2=\left ( y_1-y_2 \right )^2\)
So,
\(\sqrt{\left ( x_2-x_1 \right )^2+\left ( y_2-y_1 \right )^2}\\=\sqrt{\left ( x_1-x_2 \right )^2+\left ( y_1-y_2 \right )^2}\)
Therefore, we can say in distance formula , order in which we subtract the x coordinates and y coordinates does nor matter .
For example distance between points \(\left ( 2,3 \right )\,,\,\left ( 4,5 \right )\) is shown as below :
\(\sqrt{\left ( 4-2 \right )^2+\left ( 5-3 \right )^2}\\=\sqrt{\left ( 2-4 \right )^2+\left ( 3-5 \right )^2}\\=\sqrt{4+4}\\=\sqrt{8}\)
