Verified Answer :

\(f(x)=3x+2\\The\ domain\ D_f=\mathbb{R}\\\\g(x)=x^2+1\\The\ domain\ D_G=\mathbb{R}\\\\D_f=D_g\ therefore\ (f\times g)(x)=f(x)\times g(x)\\\\(f\times g)(x)=(3x+2)(x^2+1)=3x^3+3x+2x^2+2=\boxed{3x^3+2x^2+3x+2}\)

Answer:

\((f\times g) (x)=3x^3+2x^2+3x+2\)            

Step-by-step explanation:

Given : If \(f(x) = 3x + 2\) and \(g(x)=x^2+1\)

To find : Which expression is equivalent to \((f\times g) (x)\)?

Solution :  

We can write,

\((f\times g) (x)=f(x)\times g(x)\) ....(1)

We know, \(f(x) = 3x + 2\) and \(g(x)=x^2+1\)

Substituting the values in (1),

\((f\times g) (x)=(3x+2)\times (x^2+1)\)

Multiply term by term,

\((f\times g) (x)=3x^3+3x+2x^2+2\)

\((f\times g) (x)=3x^3+2x^2+3x+2\)

Therefore, The expression is equivalent to  \((f\times g) (x)=3x^3+2x^2+3x+2\)