What multiplication expression can be broken apart into (3x10)+ (3x10) using the distributive property
The correct answer is: 6 10
Explanation:
The distributive property is expressed as follows:
(b+c)a = ba + ca --- (1)
Method-1 (Guessing method):
Now if a = 10, b + c = 6; we can say that b = 3 and c = 3 would satisfy the condition of b+c = 6.
Plug in the values of a, b and c in (1):
(1)=> (3+3)10 = (310) + (310)
Hence 610 is the required expression.
Method-2 (Solving in reverse):
Given: (3x10)+ (3x10)
Take 10 out as common:
(3+3) 10
As you can see the expression above satisfies the distributive propery mentioned above as (1).
(3x10)+ (3x10) = (3+3) 10 = 610