Verified Answer :

dalendrk

\(bx-cx=-c\ \ \ \ \ |change\ signs\\\\cx-bx=c\\\\x(c-b)=c\ \ \ \ |divide\ both\ sides\ by\ (c-b)\\\\\boxed{x=\dfrac{c}{c-b}}\)

\(Bx-cx=-c\) 

\(x(b-c)=-c\)   \(Factor \ out \ the \ common \ term \ x\) 

\(x=- \dfrac{c}{b-c}\)   \(Divide \ both \ sides \ by \ b-c\)

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