We know the initial pressure and volume, the final pressure, and the temperature is constant, Using the G.U.E.S.S. method we can express the problem like this:
\(Givens: V_1=5 L, P_1= 115kPa, P_2= 211kPa\)
\(Unknown: V_2\)
\(Equation: \frac{V_1P_1}{P_2}=V_2\)
\(Substitute: \frac{5L*115kPa}{211kPa}= V_2\)
\(Solve: \frac{5L*115kPa}{211kPa}= 2.73 or 2.72L\)
In conclusion, your answer is either 2.73 kPa if you round or 2.72 kPa if you don't. Hope you learned from it.
