Verified Answer :

 3m2 + 2p2 − 15
 when m = 3 and p = 10.
3(3)^2+2(10)^2-15
39+2100-15
27+200_15
227_15
212

Answer:

\(212\)

Explanation:

Given

m \(= 3\)

p \(= 10\)

The equation in the question is

\(3 m^2 + 2 p^2 -15\)

In order to solve the above equation , we shall replace m and p with their n given values

On substituting "m" with \(3\) and p with \(10\) in above quadratic equation, we get -

\(3 (3)^2 + 2 (p)^2 -15\\3 * 9 + 2 * 100 - 15\\27 + 200 - 15\\212\)