Solve the equation cos x° = sin 40°, where 0 < x < 90.
For 0 < x < 90
cos (90-x) = sin (x),
and
sin (90-x) = cos(x)
Let's just try and pick the top one, the equation will become
cos (90-40) = sin (40)
Cos (50) = sin (40)
Hope this helps
Answer:
\(x\approx0.6427876097\)
Explanation:
Solve for x:
\(cos(x)=sin(40)\\\\0
Rewrite the right hand side using the following identity:
\(sin(\theta)=cos(\theta - \frac{\pi}{2} )=cos( \theta- 90)\)
Therefore:
\(cos(x)=cos(40-90)=cos(-50)\)
Since cosine function is an even function:
\(cos(-\theta) =cos(\theta)\)
Hence:
\(cos(-50)=cos(50)\)
\(cos(x)=cos(50)\)
Finally, take the inverse cosine of both sides:
\(x\approx0.6427876097\)