Verified Answer :

Willchemistry

\(\frac{d}{dx} (ax+b)(abx^7+3) =\)

Apply the product rule: \((f *g) ^{'} = f^{'} *g+f*g {'}\)

\(f=ax+b , g=abx^7+3\)

\(\frac{d}{dx} (ax+b)(abx^7+3)+ \frac{d}{dx} (abx^7+3)(ax+b)\)

\(\frac{d}{dx} (ax+b)=a\)

\(\frac{d}{dx} (b)=0\)

\(a+0 = a\)

\(\frac{d}{dx} (abx^7+3) :\)

\(\frac{d}{dx} (3)=0 ; 7 abx^6+0\)

Simplify:

\(a(abx^7+3)+7abx^6(ax+b)\)

\(= 8a^2bx^7+3a+7ab^2x^6\)

hope this helps!