How do I solve 4cos^2 x -1=0
\((cosx)^{2} = 1/4\) <=> cosx = +1/2 or cosx = -1/2;cosx = +1/2 => x = +π/3 + 2kπ, where k is an integer or x = -π/3 + 2kπ, where k is an integer;cosx = -1/2 => x = +2π/3 + 2kπ, where k is an integer or x = -2π/3 + 2kπ, where k is an integer;
Answer:
pi/3? 2pi/3?
Step-by-step explanation:
