what is the height of Fort Collins High School?
If found, use the formula, V=x/t-----------------(x=distance; t=time)
You have three known variables:
Acceleration - \(9.8m/s^2\)
Time - \(1.85s\)
Initial Velocity - \(0m/s\)
For the first part of your question:
\(v = u + at
v = (0)+(9.8)(1.1)
v = 10.78 m/s
v=11 m/s (2 significant figures)\)
For the second part of your question:
\(v=u+at
v=(0)+(9.8)(1.85)
v=18.13 m/s\)
This still needs to be converted to m/h:
\(18.13m/s = 18.13\times 3600 metres/h=65628 metres/hour
65628 metres/hour = 65628\div1600 mi/h = 40.7925 mi/h
= 41 mi/hr (2 significant figures)\)