jillinhim777 jillinhim777

25-08-2016
Chemistry

Answered

2 NO(g) + O2 (g) --> 2 NO2 (g)

What mass of NO2 is produced by the reaction of 2.40 mol NO with excess oxygen?

Verified Answer :

Willchemistry Willchemistry

27-08-2016

2 NO(g) + O2(g) = 2 NO2(g)

2 moles NO ------------ 2 moles NO2
2.40 moles NO ---------- ? ( moles NO2)

moles NO2 = 2.40 x 2 / 2

moles NO2 = 4.8 / 2

= 2.4 moles of NO2

molar mass NO2 = 46.0 g/mol

1 mole ----------- 46.0 g
2.4 moles ------- ( mass NO2)

mass NO2 = 2.4 x 46.0 / 1

mass NO2 = 110.4 / 1

= 110.4 g of NO2

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