-3y = 2x -9 solve for y
first divide by 3
y = -2/3x +3
y equals negative two-thirds x plus three
\(-3y = 2x -9\) \(y= \dfrac{2x-9}{-3}\) \(Divide \ both \ sides \ by \ -3\)\(y= -\dfrac{2x-9}{3}\)