Let
n-------> the number of nickels
d-------> the number of dimes
we know that
\(1\ nickel=\$0.05\)
\(1\ dime=\$0.10\)
so
\(0.05n+0.10d=13.30\) -----> equation A
\(n+d=175\)
\(d=175-n\) -------> equation B
substitute equation B in equation A
\(0.05n+0.10(175-n)=13.30\) ------> equation that can be used to find n
Solve for n
\(0.05n+17.5-0.10n=13.30\)
\(17.5-13.30=0.10n-0.05n\)
\(0.05n=4.2\)
\(n=84\ nickel\)
find the value of d
\(d=175-n\)
\(d=175-84=91\ dimes\)
therefore
the answer is
The equation that can be used to find n is \(0.05n+0.10(175-n)=13.30\)
The number of nickels in the collection is \(84\ nickel\)
