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  • 24-08-2016
  • Mathematics
Answered

tan(x)+tan(y)=sin(x+y)/cos(x)cos(y)

Verified Answer :

Panoyin
Panoyin Panoyin
  • 26-08-2016

\(tan(x) + tan(y) = \frac{sin(x + y)}{cos(x)cos(y)}\)
\(\frac{sin(x)}{cos(x)} + \frac{sin(y)}{cos(y)} = \frac{sin(x + y)}{cos(x)cos(y)}\)
\(\frac{sin(x)cos(y)}{cos(x)cos(y)} + \frac{sin(y)cos(x)}{cos(x)cos(y)} = \frac{sin(x + y)}{cos(x)cos(y)}\)
\(\frac{sin(x)cos(y) + sin(y)cos(x)}{cos(x)cos(y)} = \frac{sin(x + y)}{cos(x)cos(y)}\)
\(\frac{sin(x + y)}{cos(x)cos(y)} = \frac{sin(x + y)}{cos(x)cos(y)}\)

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