Verified Answer :

we have that

\(x-y=2\)

solve for y

\(y=x-2\) -------> equation \(1\)

so

Assume a value of x and then with the equation calculate the value of y

case N 1) Assume \(x=-5\)

substitute in the equation \(1\) and find the value of y

\(y=-5-2=-7\)

therefore

the answer Part 1) is

The pair of negative integers is \((-5,-7)\)

case N 2) Assume \(x=-10\)

substitute in the equation \(1\) and find the value of y

\(y=-10-2=-12\)

therefore

the answer Part 2) is

The pair of negative integers is \((-10,-12)\)