pruittlilly12
Answered

Consider the following cross:

Parent 1: YyTt

Parent 2: YyTt

Using the rules of probability, determine the probability that the offspring will show YyTT genotype?


1


8


1


16


1


2

Verified Answer :

JoshEast

The question is one of a dihybrid cross.

The picture that I attach below is a punnett cross of the parents (Yy Tt and  Yy Tt).  

So first you have to separate the two parents into gametes by pairing the alleles ( Yt , YT, yT, yt).  Then I crossed then with the punnett square and from that we see that there are two possible off spring that will would possess the genotype Yy TT (shaded gray in the diagram).

Thus the probability that a Yy TT offspring would be 2 out of 16
                   =   \(\frac{2}{16}\)
                   =   \(\frac{1}{8}\)
                   =   12.5 %

View image JoshEast

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