Answer:
\(x_1= 4\\x_2=-10\)
Step-by-step explanation:
\(x^2+6x=40\)
Since it is an equation squared to find the two values of x we can apply the formula of the solver
\(x = \frac {-b \pm \sqrt {b^2 - 4ac}}{2a}\)
we equate the equation to zero to be able to apply the solver
\(x^2+6x=40\\x^2+6x-40=0\)
\(a=1 \\b=6\\c=-40\)
\(x = \frac {-6 \pm \sqrt {(6)^2 - 4(1)(-40)}}{2(1)}\\x = \frac {-6 \pm \sqrt {36+160}}{2}\\x = \frac {-6 \pm \sqrt {196}}{2}\\x = \frac {-6 \pm \ 14}{2}\\x_1= \frac {-6 +\ 14}{2}\\x_1= \frac{8}{2}= 4\\x_2=\frac {-6 - 14}{2}\\x_2=\frac{-20}{2}= -10\)
\(x_1= 4\\x_2=-10\)
