How do you factor 64-x^2 completely?
\(64-x^2\) \(This \ fits \ the \ form \ a^2-b^2\) \(Rewrite \ it \ where \ a=8 \ and \ b=x\) \(Use \ Difference \ of \ Squares\) \(a^2-b^2=(a+b)(a-b)\)\((8+x)(8-x)\)